F2 Science Electricity Exercise Top < Instant >

for the current. If one bulb blows, the whole circuit breaks. : There are multiple paths

R2 and R3 are connected in parallel . This parallel combination is connected in series with R1.

A. Ammeter B. Voltmeter C. Ohmmeter D. Galvanometer

| | Symbol | SI Unit | Measuring Instrument | |----------------------|------------|--------------|--------------------------| | Voltage | V | Volt (V) | Voltmeter | | Current | I | Ampere (A) | Ammeter | | Resistance | R | Ohm (Ω) | Ohmmeter / Multimeter | | Power | P | Watt (W) | Wattmeter | f2 science electricity exercise top

I=VRcap I equals the fraction with numerator cap V and denominator cap R end-fraction I=612=0.5Acap I equals 6 over 12 end-fraction equals 0.5 A 4. Top Revision Exercise Questions

To rank at the top of your class in F2 science electricity, ensure you can: between conductors and insulators. Draw clear circuit diagrams using correct symbols.

A material that allows electric charge to flow easily is called: A) Insulator B) Conductor C) Resistor D) Semiconductor for the current

A hairdryer uses a current of 5 A and has a resistance of 44 Ω. Calculate the voltage needed to operate it. (Show formula, working, unit – 5 marks)

Convert the following units: (a) 5 V to kV (b) 4 A to mA (c) 3 Ω to mΩ (d) 8 W to μW

. Higher resistance leads to smaller current for a constant voltage. Circuit Types: This parallel combination is connected in series with R1

| Mistake | Correction | |---------|-------------| | Placing ammeter in parallel | Ammeter must be in series to measure current | | Placing voltmeter in series | Voltmeter must be in parallel to measure voltage | | Adding parallel resistors as ( R_1 + R_2 ) | Use ( \frac1R_p = \frac1R_1 + \frac1R_2 ) | | Forgetting that current divides in parallel | Calculate branch currents using ( I = V / R ) per branch | | Assuming voltage is same across series components | Voltage divides; current is same |

Ensure your current is in Amperes (A), not milliamperes (mA), before using Ohm's Law. Convert by dividing mA by 1,000.