Lab Activity Blood Type Pedigree Mystery Answer Key Upd ((exclusive)) Jun 2026

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Step 1: Start with the RecessivesThe easiest way to begin solving the mystery is to look for individuals with Type O blood. Because Type O is recessive, their genotype must be OO. Write this down immediately. lab activity blood type pedigree mystery answer key upd

as the primary suspects in most versions of this lab, depending on the specific blood sample found. Family Member Blood Type (Phenotype) Genotype (ABO) Earlobe Trait B+ (Determined) cap I to the cap B-th power i cap I to the cap B-th power cap I to the cap B-th power Free (unattached) cap I to the cap A-th power cap I to the cap B-th power Free (unattached) cap I to the cap A-th power i cap I to the cap A-th power i cap I to the cap A-th power i 1. Identify the Inheritance Patterns ABO Blood Type: codominance (A and B are both expressed) and multiple alleles are dominant; is recessive). Earlobe Attachment: autosomal recessive trait. "Free" earlobes ( ) are dominant over "attached" earlobes ( 2. Determine Joseph’s Genotype

We already determined the Jones family cannot have an AB child. : : Step 1: Start with the RecessivesThe

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Below is the definitive analysis of the Pendelton family lineage. Use this updated key to grade student worksheets or guide struggling lab groups. Generation I Analysis Phenotype is Type AB . His genotype must be IAIBcap I to the cap A-th power cap I to the cap B-th power . Eleanor (I-2): Phenotype is Type O . Her genotype must be . Generation II Analysis IAIBcap I to the cap A-th power cap I to the cap B-th power ) and Eleanor ( ) can only pass an IAcap I to the cap A-th power IBcap I to the cap B-th power allele from Arthur, and must pass an as the primary suspects in most versions of

Phenotype is Type O , meaning his genotype is . The Genotypic Math: Charles requires one allele from Beatrice and one allele from Edward. We know Beatrice is IAicap I to the cap A-th power i (she can provide an Edward is Type B . If Edward's genotype is IBicap I to the cap B-th power i , they can successfully produce a Type O child ( The Punnett Square (Beatrice IAicap I to the cap A-th power i IBicap I to the cap B-th power i ): IBcap I to the cap B-th power IAcap I to the cap A-th power IAIBcap I to the cap A-th power cap I to the cap B-th power IAicap I to the cap A-th power i IBicap I to the cap B-th power i (Type O)

Hi everyone,

To find the total probability of the Father and Mother having a child who is , multiply the individual probabilities: